Find the voltage in given figure
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Given :
- R 1 = 4 Ω
- R 2 = 6 Ω
- V = 50 V
To find :
- Potential difference across 6Ω resistor
How to solve :
- First we need to find the equivalent resistance of the combination
- Find the net current flowing through the circuit
- Then , find the PD across 6 Ω resistor
Solution :
R 1 are R 2 are connected in series with each other .
Equivalent resistance for n no of resistors connected in series is given by the formula ,
➜ Rs = R 1 + R 2 ... + R n
Hence ,
➜ Rs = R 1 + R 2
➜ Rs = 4 + 6
➜ Rs = 10 Ω
Now , let us find the net current flowing through the circuit .
By applying ohm's law ,
➜ I = V / Rs
➜ I = 50 / 10
➜ I = 5 A
We know that , in series combination the current flowing through both the resistors is the same , but the potential difference across both the resistors is different .
Now , let us find the PD across 6 Ω resistor
➜ V 2 = I x R 2
➜ V 2 = 5 x 6
➜ V 2 = 30 V
The potential difference across 6 Ω resistor is 30 V
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