Question

Find the voltage of power supply to which a bulb of rating 200W- 220V is connected to consume energy at the rate of 100 J/s.​

Answer 1

Answer:

V = 155.56 volt

Step-by-step explanation:

Power of Bulb = 200W

Bulb can Operate at Voltage = 220V

Now we find the Resistance of bulb

P = V×V /R

200 = 220× 220 /R

200= 48400 /R

R = 48400/200

R = 242 ohm

Now we produce 100Joule/s

P = V×V /R

100 = V× V /242

V×V = 24200

V^2 = 24200

V = 155.56 volt

Answer 2

Answer:

The power dissipated by an electric bulb is given as P = VI.

In this case, Power P = 100 W and Voltage V = 220 V.

So, current I is I = P/V = 100/220 = 0.45 A.

When the supplied voltage is 110 V, the power consumed will be P=VI = 110 * 0.45 = 50 W.

Hence, the power consumed when operated at 110 V is 50 W.