Question

find the volume and number of molecules present in 88g carbon dioxide at stp​

Answer 1

Answer:

No of moles= 88/44 =2

therefore no. of molecules =

6.023 \times {10}^{23} \times 2

therefore no.of molecules= 12.046*10^23

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Answer 2

Answer:

88 g co2 is 2 moles of co2 ( 1 mole co2 = 44 gm) . Since 1 mole co2 has 2 moles of O atom 2 moles ie 88 gm will have 4 moles which is 4 times avogardos no of atom ie 4* 6.023 *10^23. The chemical formula CO2 tells us that one mole of the compound contains two moles of oxygen.

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