Find the volume and surface area of a cylinder whose area of base =38.5 cm^2 and height =9 cm
Answers
Answered by
17
Hi there!!
Here's your answer:
Given:
Area of base = 38.5 cm^2
( Area of base of the cylinder is area of circle as shape of base of cylinder is circle)
Area of circle = πr^2 = 38.5 cm ^2
height = 9 cm
To find:
Volume and surface area
Solution:
Volume = πr^2h
= 38.5 × 9
= 346.5
Therefore volume is 346.5 cm^3
For surface area it is necessary to find radius first
volume = πr^2h
346.5 = 22/7 × r^2 × 9
346.5 × 7 / 22 × 9 = r^2
38.5 × 7 / 22 = r^2
1.75 × 7 = r^2
12.25 = r^2
√12.25 = r
3.5 = r
Therefore radius is 3.5 cm
Surface area = 2πr ( r + h )
= 2 × 22/7 × 3.5 ( 3.5 + 9 )
= 2 × 22/7 × 35/10 ( 12.5 )
= 22 × 12.5 ( After cancellation )
= 275 cm^2
Therefore surface area is 274 cm^2
Hope this helps ☺️
Here's your answer:
Given:
Area of base = 38.5 cm^2
( Area of base of the cylinder is area of circle as shape of base of cylinder is circle)
Area of circle = πr^2 = 38.5 cm ^2
height = 9 cm
To find:
Volume and surface area
Solution:
Volume = πr^2h
= 38.5 × 9
= 346.5
Therefore volume is 346.5 cm^3
For surface area it is necessary to find radius first
volume = πr^2h
346.5 = 22/7 × r^2 × 9
346.5 × 7 / 22 × 9 = r^2
38.5 × 7 / 22 = r^2
1.75 × 7 = r^2
12.25 = r^2
√12.25 = r
3.5 = r
Therefore radius is 3.5 cm
Surface area = 2πr ( r + h )
= 2 × 22/7 × 3.5 ( 3.5 + 9 )
= 2 × 22/7 × 35/10 ( 12.5 )
= 22 × 12.5 ( After cancellation )
= 275 cm^2
Therefore surface area is 274 cm^2
Hope this helps ☺️
Answered by
5
hope it helps u............
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