Find the volume and TSA of hemisphere of radius 3.5cm
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r
![r = 3.5 \\ so \: tsa \: wil \: be \: 2\pi \: r^{2} r = 3.5 \\ so \: tsa \: wil \: be \: 2\pi \: r^{2}](https://tex.z-dn.net/?f=r+%3D++3.5+%5C%5C++so++%5C%3A+tsa+%5C%3A+wil+%5C%3A+be+%5C%3A+2%5Cpi+%5C%3A+r%5E%7B2%7D+)
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Hey Mate!
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Here is your answer :
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Given,
Radius of sphere = 3.5 = 7/2
![volume \: of \: sphere \: = \frac{2}{3} \pi \: {r}^{3} \\ \\ = \frac{2}{3} \times \frac{22}{7} \times \frac{7}{2} \times \frac{7}{2} \times \frac{7}{2} \\ \\ = \frac{539}{6} \\ \\ = 89.83 {cm}^{3} \\ \\ surface \: area \: = 3\pi \: {r}^{2} \\ \\ = 3 \times \frac{22}{7} \times \frac{7}{2} \times \frac{7}{2} \\ \\ = \frac{231}{2} \\ \\ = 115.5 {cm}^{2} volume \: of \: sphere \: = \frac{2}{3} \pi \: {r}^{3} \\ \\ = \frac{2}{3} \times \frac{22}{7} \times \frac{7}{2} \times \frac{7}{2} \times \frac{7}{2} \\ \\ = \frac{539}{6} \\ \\ = 89.83 {cm}^{3} \\ \\ surface \: area \: = 3\pi \: {r}^{2} \\ \\ = 3 \times \frac{22}{7} \times \frac{7}{2} \times \frac{7}{2} \\ \\ = \frac{231}{2} \\ \\ = 115.5 {cm}^{2}](https://tex.z-dn.net/?f=volume+%5C%3A+of+%5C%3A+sphere+%5C%3A++%3D++%5Cfrac%7B2%7D%7B3%7D+%5Cpi+%5C%3A++%7Br%7D%5E%7B3%7D++%5C%5C++%5C%5C++%3D++%5Cfrac%7B2%7D%7B3%7D++%5Ctimes++%5Cfrac%7B22%7D%7B7%7D++%5Ctimes++%5Cfrac%7B7%7D%7B2%7D++%5Ctimes++%5Cfrac%7B7%7D%7B2%7D++%5Ctimes++%5Cfrac%7B7%7D%7B2%7D++%5C%5C++%5C%5C++%3D++%5Cfrac%7B539%7D%7B6%7D++%5C%5C++%5C%5C++%3D+89.83+%7Bcm%7D%5E%7B3%7D++%5C%5C++%5C%5C+surface+%5C%3A+area+%5C%3A++%3D+3%5Cpi+%5C%3A++%7Br%7D%5E%7B2%7D++%5C%5C++%5C%5C++%3D+3+%5Ctimes++%5Cfrac%7B22%7D%7B7%7D++%5Ctimes++%5Cfrac%7B7%7D%7B2%7D++%5Ctimes++%5Cfrac%7B7%7D%7B2%7D++%5C%5C++%5C%5C++%3D++%5Cfrac%7B231%7D%7B2%7D++%5C%5C++%5C%5C++%3D+115.5+%7Bcm%7D%5E%7B2%7D+)
HOPE THIS HELPS U...
~~~~~~~~
Here is your answer :
=============================
Given,
Radius of sphere = 3.5 = 7/2
HOPE THIS HELPS U...
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