Question

find the volume at NTP of oxygen required to completely burn 1 kg of coal(100% carbon)

Answer 1

QuesTion :-

Volume at NTP of oxygen required to completely burn 1 kg of coal (100 % carbon) is ?

SoluTion :-

Mass of C = 1000 g

$\sf {Moles\ of\ C=\frac{1000}{12}=83.34\ moles }\\\\\\\sf {C + O_{2} \longrightarrow CO_{2}}$

1 moles C requires 1 mole O₂    to burn.

Thus, 83.34 mole C requires 83.34 moles O₂  

At NTP, 1 mole gas occupies 22.4 litres.

83.34 moles occupies 83.34 × 22.4 = 1.86 × 10³  L

Answer 2

Answer:

Mass of C = 1000 g

1 moles C requires 1 mole O₂    to burn.

Thus, 83.34 mole C requires 83.34 moles O₂  

At NTP, 1 mole gas occupies 22.4 litres.

83.34 moles occupies 83.34 × 22.4 = 1.86 × 10³  L

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Explanation: