Question

Find the volume, C.S.A, T.S.A of a cone if the radius of its base is 1.5 cm and its perpendicular height is 5 cm.
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Answer 1

Answer:

Step-by-step explanation:GIVEN

            RADIUS =1.5

             LENTH=5CM

                 CSA OF CONE =PIE r l

                                            =22/7*1.5*5

                                           =23.6

                 TSA OF CONE =[PIE r{L+R}]

                                            =22/7*5{5+1.5}

                                           =102.14

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{C.S.A\:of\:cone=24.5862\:cm}^{2}}}$

$\green{\therefore{\text{T.S.A\:of\:cone=31.6512\:cm}^{2}}}$

$\green{\therefore{\text{Volume\:of\:cone=11.775\:cm}^{3}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{ \underline \bold{Given : }} \\ : \implies \text{Radius(r) = 1.5 \: cm} \\ \\ : \implies \text{Height(h) = 5 \: cm} \\ \\ \red{ \underline \bold{To \: Find : }} \\ : \implies \text{C.S.A\: of \: cone = ?}\\\\ :\implies \text{T.S.A\:of\:cone=?}\\\\ :\implies \text{Volume\:of\:cone=?}$

• According to given question :

$\bold{As \: we \: know \: that} \\ : \implies \text{Slant \: height = hypotenuse \: of \: right \: circular \: cone} \\ \\ : \implies {h}^{2} = {p}^{2} + {b}^{2} \\ \\ :\implies {l}^{2} = {5}^{2} + {1.5}^{2} \\ \\ : \implies {l}^{2} = 25 + 2.25 \\ \\ : \implies {l} = \sqrt{27.25} \\ \\ \green{: \implies {l} = 5.22 \: cm} \\ \\ \bold{As \: we \: know \: that \: C.S.A \: of \: cone}\\ : \implies \text{C.S.A\: of \: cone} = \pi rl \\ \\ : \implies \text{C.S.A \: of \: cone} = \frac{22}{7} \times 1.5 \times 5.22 \\ \\ : \implies \text{C.S.A \: of \: cone} =3.14 \times 7.83\\ \\ \green{ : \implies \text{C.S.A\: of \: cone} =24.5862\: {cm}}^{2}$

$\bold{As \: we \: know \: that \: T.S.A \: of \: cone}\\ : \implies \text{T.S.A\: of \: cone} = \pi rl +\pi r^{2}\\ \\ : \implies \text{T.S.A \: of \: cone} = 24.5862+3.14\times( 1.5)^{2}\\ \\ : \implies \text{T.S.A\: of \: cone} =24.5862 + 7.065\\ \\ \green{ : \implies \text{T.S.A\: of \: cone} =31.6512\: {cm}}^{2}$

$\bold{As \: we \: know \: that \: Volume \: of \: cone}\\ : \implies \text{Volume\: of \: cone} = \frac{1}{3}\pi r^{2}h\\ \\ : \implies \text{Volume \: of \: cone} = \frac{1}{3} \times \frac{22}{7}\times 1.5^{2} \times5\\ \\ : \implies \text{Volume\: of \: cone} = 3.14\times 3.75\\ \\ \green{ : \implies \text{T.S.A\: of \: cone} =11.775\: {cm}}^{3}$