find the volume covered surface area and the total surface area of a cone whose height and VII height 6 cm and 10 cm respectively
Answers
Answer:
h=6cm
slant height, l=10cm
radius ,r=?
Now, l²=r²+h²
r²=l²-h²
r²=(10cm)²-(6cm)²
r²=100cm²-36cm²
r²=64cm²
r=√(64cm²)
r=8cm.
Volume of cone
=πr²h/3
=3.14×(8cm)²×6cm/3
=401.92cm³
CSA of cone
=πrl
=(22/7)×8cm×10cm
=251.2cm²
TSA of cone
=πr(l+r)
=(22/7)×8cm(10cm+8cm)
=(22/7)×8cm×18cm
=452.16cm²
Correct Question :-
Find the volume , curved surface area and total surface area of cone whose height and slant height is 6 cm and 10 cm respectively.
Given :
Height of the cone is 6 cm and Slant height is 10 cm respectively.
To find :
What is Volume of cone?
What is CSA of cone ?
What is TSA of cone ?
Solution :
Using formula ,
Now, According to the Question :-
Firstly find out the radius ,
↠ Slant height² (l²) = Height²(h²) + Radius²(r²)
↠ 10² = 6² + r²
↠ 100 = 36 + r²
↠ r² = 100 - 36
↠ r² = 64
↠ r = √64
↠ r = 8 cm
Now we got the radius
So , we can easily find out the volume by using the formula :-
1. Volume of cone = 1/3 πr²h
↠ 1/3 × 22/7 × 8² × 6
↠ 22/7 × 64 × 2
↠ 2816/7
↠ 402.29 cm³
2. CSA of cone = π × r × l
↠ 22/7 × 8 × 10
↠ 1760/7
↠ 251.43 cm²
3. TSA of cone = πr( l + r )
↠ 22/7 × 8 (10 + 8)
↠ 22/7 × 8 × 18
↠ 3168/7
↠ 452.57 cm²
Additional Information :-
❥ Perimeter of Rectangle = 2( L + B )
❥ Perimeter of square = 4 × Side
❥ Perimeter of triangle = AB + BC + CA
❥ Area of Rectangle = L × B
❥ Area of Square = ( side ) ²
❥ Area of Rhombus = Product of Diagonal/2.
❥ Area of Parallelogram = Base × Height.
❥ Area of triangle = 1/2 × base × height .