find the volume in cm^3 of a piece of metal of density 5000 kg/m^3 and which weight 10.8 N g=10m/s^2
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D=500 kg/m^3
F=10.8 N
g=10 m/s^2
m=F/a=10.8/10=1.08 Kg
V=m/D=1.08/5000 m^3
V=0.000216
thamusmile:
a truck of mass 5000 kg acceleration from 25 m/s to 35 m/s . find the change in itd kinetic energy
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Answer= 216
Explanation:
Volume = Mass / Density
Mass = W/g
= 10.8 kg x m/s^2 / 10 m/s^2 = 1.08 kg = 1080 gms
Volume = 1080 / 5000 kg/m^3 = 1080 gms / 5 gms/ cc = 216 cm^3
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