Physics, asked by thamusmile, 1 year ago

find the volume in cm^3 of a piece of metal of density 5000 kg/m^3 and which weight 10.8 N g=10m/s^2

Answers

Answered by siman26
1

D=500 kg/m^3

F=10.8 N

g=10 m/s^2

m=F/a=10.8/10=1.08 Kg

V=m/D=1.08/5000 m^3

V=0.000216


thamusmile: a truck of mass 5000 kg acceleration from 25 m/s to 35 m/s . find the change in itd kinetic energy
siman26: m=5000kg v=35-25=10m/s KE=(1/2) MV^2=0.5×5000×100=50000J
Answered by ainahamlyn
0

Answer= 216

Explanation:

Volume = Mass  / Density

Mass = W/g

= 10.8 kg x m/s^2  / 10 m/s^2 = 1.08 kg = 1080 gms

Volume = 1080 / 5000 kg/m^3 = 1080 gms / 5 gms/ cc = 216 cm^3

Similar questions