Question

Find the volume occupied by 0.1 mol of nitrogen

Answer 1

Answer:

Volume 'V'=2.243 L

Explanation:

Assume STP of 1 atm and 273°k for the pressure and the temperature.

We can Use the Ideal Gas Law equation that PV=nRT

Here,

P=1 atm

T=273°k

R=0.0821 ($\frac{atm L}{mol K}$)

n=0.1 moles

v=?

So, $V=\frac{nRT}{P}$

substitute the values in above equation

    V=[$\frac{(0.1)(0.0821)(273)}{1}$]

     V=2.243L

Therefore the volume occupied by 0.1 mol of nitrogen is 2.24L