Question

Find the volume occupied by (a) 14g of N2 at STP.

Answer 1

1 mole of N2 gas at NTP occupies 22.4Lt
So,14 g of N2 will occupy 11.2 Lt

Answer 2

Given:

14 grams of nitrogen gas.

To find:

We have to find its volume at STP.

Solution:

The atomic weight of a nitrogen atom is 14 grams.

Thus the molecular weight of nitrogen gas is 14×2=28 grams.

At STP 1 mole of any gas has a volume of 22.4 litres.

Thus we can write-

28 grams or 1 mole of nitrogen gas has a volume of 22.4 litres.

So, 14 grams of nitrogen gas has a volume of 22.4×14/28=11.2 litres.

Thus at STP 14 grams of nitrogen gas has a volume of 11.2 litres.