Question

find the volume of 0.1M NaOH solution required to neutralize completely 22.5ml of 0.125M H2SO4​

Answer 1

Answer:

0.10M NaOH (0.10mol/lit NaOH)

0.2M H3PO4 ( 0.2 mol/lit H3PO4)

15 ml of H3PO4 or 0.015 lit of H3PO4

Find volume of NaOH needed to neutralize the solution

Relate moles of H3PO4 with the moles of NaOH with the helps of coefficients in front of NaOH and H3PO4 seen in balanced equations.

moles ↔ Litre use definition of molarity (moles/litrs)

Start with what is given for H3PO4

0.015 lit of H3PO4 x 0.2 moles of H3PO4 / lit of H3PO4 x 3 moles of NaOH/1 mole of H3PO4 x lit of NaOH/0.1 mol of NaOH = 0.09 lit or 90 ml.

The same colors in above equations cancel our leaving lit of NaOH as final answer.

Answer 2

Answer:

i have given a hint for u

Explanation:

here we should use a formula i.e, MKV/1000 is constant say it as x

for  H2SO4; M=0.125M V=22.5ml K=49

similarly calculate for NaOH and equate them.