Question

Find the volume of 4.4g of CO2 at S.T.P. ?

Answer 1

given, weight of Carbon dioxide = 4.4 g

as we know , molecular weight of CO2 = atomic mass of C + 2 × atomic mass of O

we know, atomic mass of oxygen, {e.g., O} is 16g/mol

and atomic mass of carbon {e.g., C} is 12g/mol

so, molecular mass of CO2 = 12 + 2 × 16 = 12 + 32 = 44g/mol

now, number of mole = 4.4/44 = 0.1

A basic concept is that, 1 mole of an ideal gas at STP occupied 22. 4L volume .

so, 0.1 mole of CO2 occupied 22.4 × 0.1 = 2.24L volume at STP { standard temperature and pressure} .

Answer 2

Answer:

Molecular mass of CO2 = 44 g

1 Mol CO2 occupies 22.4l

ie, 44 g CO2 = 22.4 l

so, 4.4 CO2 ( 44 * 0.1 =4.4 ) = 22.4 * 0.1

=2.24 L