find the volume of 6.023*10^22 molecules of NH3
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2
Answer:
Remember that STP is defined as 0 °C and 1 bar.
n
=
0.100 02 mol
R
=
0.083 14 bar⋅L⋅K
-1
mol
-1
T
=
(0 + 273.15) K
=
273.15 K
p
=
1 bar
V
=
n
R
T
p
=
0.100 02
g
×
0.083 14
bar
⋅
L
⋅
K
-1
mol
-1
×
273.15
K
1
bar
=
2.271 L
Method 2. Using the molar volume
We know that there are 0.100 02 mol of
NH
3
.
We also know that the molar volume of a gas is 22.71 L at STP.
∴
V
=
0.100 02
mol NH
3
×
22.71 L NH
3
1
mol NH
3
=
2.271 L NH
3
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