Question

find the volume of 6.023*10^22 molecules of NH3​

Answer 1

Answer:

Remember that STP is defined as 0 °C and 1 bar.

n

=

0.100 02 mol

R

=

0.083 14 bar⋅L⋅K

-1

mol

-1

T

=

(0 + 273.15) K

=

273.15 K

p

=

1 bar

V

=

n

R

T

p

=

0.100 02

g

×

0.083 14

bar

⋅

L

⋅

K

-1

mol

-1

×

273.15

K

1

bar

=

2.271 L

Method 2. Using the molar volume

We know that there are 0.100 02 mol of

NH

3

.

We also know that the molar volume of a gas is 22.71 L at STP.

∴

V

=

0.100 02

mol NH

3

×

22.71 L NH

3

1

mol NH

3

=

2.271 L NH

3