Question

Find the volume of 6.023x10 22
molecules of NH₃
​

Answer 1

Explanation:

1 1 answer

Calculate the moles of ammonia. n=6.023×1022molecules NH3 ×1 mol NH36.022×1023molecules NH3 =0.100 02 mol NH3. Calculate the volume at STP. Remember that STP is defined as 0 °C and 1 bar. n=0.100 02 mol. R=0.083 14 bar⋅L⋅K-1mol-1. T=(0 + 273.15) K=273.15 K. p=1

Answer 2

Answer:

Calculate the moles of ammonia. n=6.023×1022molecules NH3 ×1 mol NH36.022×1023molecules NH3 =0.100 02 mol NH3. Calculate the volume at STP. Remember that STP is defined as 0 °C and 1 bar. n=0.100 02 mol. R=0.083 14 bar⋅L⋅K-1mol-1. T=(0 + 273.15) K=273.15 K. p=1 bar.

Explanation:

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