Question

Find the volume of 900 g of cooking oil whose density is 0.9 g/cm^3. Give the answer in litres.one who gives the correct answer i will mark as brainliest​

Answer 1

Answer:

The required volume is 1 L

Explanation:

Given :

900 g of cooking oil whose density  is 0.9 g/cm³

To find :

the volume of the cooking oil

Solution :

• Density of a substance is its mass per unit volume.

• SI unit of density is kg/m³

• It is expressed as,

        $\boxed{ \rm \rho =\frac{m}{V}}$

where

m denotes the mass

V denotes the volume

Substitute the given values,

0.9 g cm⁻³ = 900 g/V

V = 900 g/0.9 g cm⁻³

V = 1000 cm³

V = 1 L   [ ∵ 1000 cm³ = 1 L ]

Answer 2

Answer:

• 1000 cm³ or 1 L

Explanation:

Given

• Mass of cooking oil = 900 g
• Density of cooking oil = 0.9 g/cm³

To find

• Volume of cooking oil.

Solution

➝ Density = Mass/Volume

↪ Here,

• Density = 0.9 g/cm³
• Mass = 900 g
• Density = ?

↪ Substituting we get,

• Density = 900/0.9
• Density = 1000 cm³

( g and g get cancelled)

➝ 1 L = 1000 cm³

∴ Density of cooking oil is 1 L