Question

Find the volume of a and b in the following

√3+√2÷√3-√2=a+b√6

Answer 1

Answer:

answer right or wrong write on comment box

Answer 2

Answer:

a=5,b=2

Step-by-step explanation:

Given;-$\frac{\sqrt{3}+\sqrt{2}}{\sqrt{3}-\sqrt{2}}=a+b\sqrt{6}$

To find;-a and b

$\frac{\sqrt{3}+\sqrt{2}}{\sqrt{3}-\sqrt{2}}=a+b\sqrt{6}$

Taking L.H.S and multiplying numerator and denominator with$\frac{\sqrt{3}+\sqrt{2}}{\sqrt{3}+\sqrt{2}}$

$\frac{\sqrt{3}+\sqrt{2}\times \sqrt{3}+\sqrt{2}}{\sqrt{3}-\sqrt{2}\times \sqrt{3}+\sqrt{2}}$

$\frac{(\sqrt{3}+\sqrt{2})^{2}}{3-2}$      $using(a+b)(a-b)=a^{2}-b^{2}$

$\frac{3+2+2\sqrt{6}}{1}$     $using(a+b)^{2}=a^{2}+b{2}+2ab$

$5+\sqrt{6}$

Comparing with the R.H.S we get,

$5+\sqrt{6}=a+b\sqrt{6}$

a=5,b=2