Math, asked by sarakhadri123, 2 months ago

Find the volume of a cuboid whose length, breadth and height are 8abc^2, -3abc and 2a^2bc

Answers

Answered by george0096
6

Answer:

  • Volume of a cuboid with sides as 8abc², -3abc and 2a²bc is -48a⁴b³c⁴.

Step-by-step explanation:

Given that:

  • Length of the cuboid is 8abc².
  • Breadth of the cuboid is -3abc.
  • Height of the cuboid is 2a²bc.

To Find:

  • Volume of the cuboid.

As we know that:

  • Volume of a cuboid = (l × b × h) cubic units

Where,

  • l = Length of the cuboid
  • b = Breadth of the cuboid
  • h = Height of the cuboid

Substituting the values:

Volume of the cuboid = {8abc² × (-3abc) × 2a²bc}

Multiplying the numbers,

\sf{\longrightarrow \{8 \times (-3) \times 2\} \times a^{1+1+2}b^{1+1+1}c^{2+1+1}}

Solving further,

\sf{\longrightarrow -48 \times a^{4}b^{3}c^{4}}

Multiplying the values,

\sf{\longrightarrow -48a^{4}b^{3}c^{4}}

Hence, volume of the cuboid is -48a⁴b³c⁴.

Know more:

  • Diagonal of a cuboid = \sf{\sqrt{l^2+b^2+h^2}} units
  • Total surface area of a cuboid = 2(lb + lh + bh) sq. units
  • Lateral surface area of a cuboid = {2(l + b) × h} sq. units
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