Question

Find the volume of a cuboid whose length is (3x + 4) units and its
breadth and height is (3x - 4) units each.
pls solve my question​

Answer 1

Step-by-step explanation:

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Answer 2

The $volume of cuboid=27x^3-36x^2-48x+64$ cubic units

Step-by-step explanation:

Given that length of a cuboid is 3x+4 units breadth and height is 3x-4 units

Therefore length=3x+4 ,breadth=3x-4 and height=3x-4

To find the volume of a cuboid :

We know that the $volume of cuboid=length\times breadth\times height$ cubic units

• Now substitute the values in the formula we have
• $volume of cuboid=3x+4\times (3x-4)\times (3x-4)$
• $=(3x+4)\times (3x-4)^2$
• $=(3x+4)\times ((3x)^2-2(3x)(4)+4^2)$ ( by using the identity $(a-b)^2=a^2-2ab+b^2$ )
• $=(3x+4)\times (9x^2-24x+16)$
• $=3x(9x^2)+3x(-24x)+3x(16)+4(9x^2)+4(-24x)+4(16)$ ( by using the distributive property )
• $=27x^3-72x^2+48x+36x^2-96x+64$
• $=27x^3-36x^2-48x+64$

Therefore $volume of cuboid=27x^3-36x^2-48x+64$ cubic units