Question

Find the volume of a cuboids' whose dimensions are as follows: I = 12 cm * b = 7.5 cm and h = 22 cm​

Answer 1

Answer:

volume : 198 cm^3

Step-by-step explanation:

Volume of cuboid : l*b*h

volume of cuboid = 12 * 7.5 * 22 = 198 cm^3

Answer 2

Step-by-step explanation:

Question :-

• Find the volume of cuboid whose dimensions are 12 cm × 7.5 cm × 22 cm respectively.

To Find :-

• Volume of cuboid.

Solution :-

Given :

• Length = 12 cm
• Breadth = 7.5 cm
• Height = 22 cm

By using the formula,

${\sf{\longrightarrow Volume\ of\ cuboid\ =\ l \times b \times h}}$

Where,

• l = length
• b = breadth
• h = height

According to the question, by using the formula, we get :

${\sf{\longrightarrow Volume\ of\ cuboid\ =\ l \times b \times h}}$

${\sf{\longrightarrow 12 \times 7.5 \times 22}}$

${\sf{\longrightarrow 1,980\ cm^3}}$

$\therefore$ Hence, volume of cuboid is 1,980 cm³.

More To Know :-

$\begin{array}{|c|c|c|}\cline{1-3}\bf Shape&\bf Volume\ formula&\bf Surface\ area formula\\\cline{1-3}\sf Cube&\tt l^3}&\tt 6l^2\\\cline{1-3}\sf Cuboid&\tt lbh&\tt 2(lb+bh+lh)\\\cline{1-3}\sf Cylinder&\tt {\pi}r^2h&\tt 2\pi{r}(r+h)\\\cline{1-3}\sf Hollow\ cylinder&\tt \pi{h}(R^2-r^2)&\tt 2\pi{rh}+2\pi{Rh}+2\pi(R^2-r^2)\\\cline{1-3}\sf Cone&\tt 1/3\ \pi{r^2}h&\tt \pi{r}(r+s)\\\cline{1-3}\sf Sphere&\tt 4/3\ \pi{r}^3&\tt 4\pi{r}^2\\\cline{1-3}\sf Hemisphere&\tt 2/3\ \pi{r^3}&\tt 3\pi{r}^2\\\cline{1-3}\end{array}$