Question

Find the volume of a frustum of a right pyramid whose lower base is a square with a side 5 in whose upper base is a square with a side 3 in?

Answer 1

here is your answer

volume of the frustum = 1/3*[area of the lower base + area of the upper base + sqrt(area of the lower base)(area of the upper base)]*height

the base is a square so the area of the square = "s^2" 

v = 1/3*[5^2 + 3^2 + sqrt(5^2*3^2)]*12 

v = 1/3*[25 + 9 + 15]*12 
v = 196 cubic inches

hope you understand

Answer 2

A frustrum of a pyramid could be defined as an entire pyramid, minus a smaller pyramid taken off the precise. So if we can calculate the volumes of those 2 pyramids, their distinction is the respond. to try this, we would desire to discern the top of the full element, which include the area of the pyramid that's "taken off the precise" and isn't any longer there. to try this, we use the actual incontrovertible fact that the ratio of the heights of the better and smaller pyramids to the sizes of their bases is a relentless: (h-12)/3 = h/5 5h - 60 = 3h 2h = 60 h = 30 So the better pyramid has a top of 30 in. and a base with components of 5 in. The smaller pyramid has a top of (30-12)=18 in. and a base with components of three in. the quantity of the frustrum is the version of the volumes of those 2 pyramids: 30 * 5^2 / 3 - 18 * 3^2 / 3 = 750/3 - 162/3 = 250 - fifty 4 = 196 cubic inc