find the volume of a frustum of base raddi 7cm and 3.5cm and height 2cm
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R=7cm
r=3.5cm
Ht=2cm
Volume =πh/3(R²+r²+R×r)
=22×2/7×3(7²+3.5²+7×3.5)
=44/21(49+12.25+24.5)
=44/21(85.75)
=179.67 cm³
Answered by
1
Here given R₁ = 7 cm ,R₂ = 3.5 cm and height = 2 cm.
To find = Volume of a frustum of a cone.
Volume of frustum of a cone = πh/3 ( R₁² + R₂² + R₁ × R₂ )
= 22/7 × 2/3 ( 7² + 3.5² + 7 × 3.5 )
= 44/21 ( 49 + 12.25 + 24.5 )
= 44/21 × 85.75
= 3773/21
= 179.67 cm³ approx.
To find = Volume of a frustum of a cone.
Volume of frustum of a cone = πh/3 ( R₁² + R₂² + R₁ × R₂ )
= 22/7 × 2/3 ( 7² + 3.5² + 7 × 3.5 )
= 44/21 ( 49 + 12.25 + 24.5 )
= 44/21 × 85.75
= 3773/21
= 179.67 cm³ approx.
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