Question

Find the volume of a right circular cone 1.02 m high, if the radius of its base is 28 cm.​

Answer 1

Given:

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• Height of right circular cone is 1.02 m
• Radius of its base is 28 m

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To find:

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Volume of the right circular cone.

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Solution:

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We know that formula for finding volume of a right circular cone is 1/3 $\pi$ r$^{2}$ h

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So, volume of the right circular cone = 1/3 $\pi$ r$^{2}$ h

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= 1/3 × 22/7 × 28 × 28 × 102

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= 83776 cm$^{3}$

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Know more:

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1. Curved surface area of a right circular cone = 1/2 × (arc length) × (radius)

= 1/2 × 2 πr × l

= πrl

Hence, the area of the curved surface of a right circular cone of radius r and slant height l is given by

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S = πrl

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Also, S = 1/2 ×(2πr) × l

$\implies$ S = 1/2 {(Circumference of base) × (slant height)}

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2. Total surface area of the cone = Curved surface area + Area of the base

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= πrl + πr$^{2}$

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= πr (l + r)

Answer 2

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Find the volume of a right circular cone 1.02 m high, if the radius of its base is 28 cm.

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• hight =1.02m
• radius = 28cm

$\large\dag \ {{\boxed {\pink{\rm{formula \: used\: \ \: }}}}}††$

$\dag \ {{\boxed {\ \: {\rm{ \bf Volume \: of \: a \: cone = \frac{1}{3} \pi \ {r}^{2} h\: \: \ \: }}}}}†$

$\huge {\underline {\mathfrak{ \red a \blue n \green \pink s \orange w\purple e\red r\: - }}} </p><p>$

$\bf Volume \: of \: a \: cone = \frac{1}{3} \pi \ {r}^{2} h$

$\bf height =1.02 \: m=102 \: cm$

$\bf So, \: volume \: of \: the \: given \: cone = \frac{1}{3} \times \frac{22}{7} \ \times {28}^{2} \times 102$

$\bf=83776 \: {cm}^{3}$

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