Question

find the volume of an iron hollow pipe whose outer radius is 14 cm and inner radius is 7 cm with its length as 1m​

Answer 1

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Inner radius, r = 6 cm

Thickness, t = 1 cm

Outer radius, R = 6+1 = 7 cm

Therefore,

Volume of steel required =

32 πR 3 − 32 πr 3

= 32 × 7/22×7 3 − 32 × 722 ×6 3

=

21

5588

cm

3

Answer 2

Answer:

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Inner radius, r = 6 cm

Thickness, t = 1 cm

Outer radius, R = 6+1 = 7 cm

Therefore,

Volume of steel required =

32 πR 3 − 32 πr 3

= 32 × 7/22×7 3 − 32 × 722 ×6 3

=

21

5588

cm

3