Question

find the volume of CO2 at NTP obtained on heating 10 g of 90% pure limestone

Answer 1

 Limestone is essentially CaCO3; molar mass of CaCO3 = 100 g/mol 
10 gm of 100% pure would be 10 gm of CaCO3 
90% pure means you have only 9 gms of CaCO3 in the 10gm sample 
9 gms/100gm/mol = 0.09 moles of CaCO3 
When heated 1 mole of CaCO3 yields 1 moles of CO2 
0.09 moles of CO3 will yield 0.09 moles of CO2 
1 mole of CO2 = 22.4 liters 
22.4 liters/mol x 0.09 moles = 2.016 liters

Answer 2

Answer:

Explanation:anandawasthi2002

Secondary SchoolScience 8+4 pts

Find the volume of CO2 at NTP obtained on heating 10 g of 90% pure limestone

Report by Meshb9hupana

Limestone is essentially CaCO3; molar mass of CaCO3 = 100 g/mol

10 gm of 100% pure would be 10 gm of CaCO3

90% pure means you have only 9 gms of CaCO3 in the 10gm sample

9 gms/100gm/mol = 0.09 moles of CaCO3

When heated 1 mole of CaCO3 yields 1 moles of CO2

0.09 moles of CO3 will yield 0.09 moles of CO2

1 mole of CO2 = 22.4 liters

22.4 liters/mol x 0.09 moles = 2.016 liters