Question

find the volume of Co2 obtained at STP by heating 50 grams of Caco3 ​

Answer 1

Answer:

11.2 L

Explanation:

on heating CaCO₃

CaCO3= CaO + CO2

1 mole of CaCO₃ gives 1 mole of CO₂

at STP 1 mole = 22.4 L

given :

50 grams of CaCO₃ is heated .

which is equal to  0.5 mole.

so , 0.5 mole of CaCO₃ gives 0.5 mole of CO₂.

0.5 moles = 11.2 L ( at STP )

Answer 2

Answer:

11.2lit of co2 can be obtained