Question

find the volume of cone when its height is 6 cm and diameter of its base is 14 cm plzz answer my question it's Argent​

Answer 1

Answer:

308 $cm^3$

Step-by-step explanation:

Height of Cone = $6\:cm$

Diameter of Cone = $14\:cm$

Radius of Cone = $\frac{14}{2}\:cm = 7\:cm$

Volume of Cone = $\frac{1}{3}\pi r^2 h$

$\Rightarrow \frac{1}{3} \pi 7^2 6 \:cm^3$

$\Rightarrow \frac{1}{3} \cdot \frac{22}{7} \cdot 49 \cdot 6 \:cm^3$

$\Rightarrow 22 \cdot 7 \cdot 2 \:cm^3 = 308 \:cm^3$

Answer 2

Answer:-

The Required volume of cone is 308 cm².

Explanation:-

Given:-

• Height of cone (h) = 6 cm.

• Diameter of its base (d) = 14 cm.

To Find:-

• The volume of the cone.

Formula Used:-

$\\ \bf\implies Volume = \dfrac{1}{3}\pi r^2 h.$

Where r is radius of the base of cone.

Solution,

Since diameter is given, so radius would be $\dfrac{d}{2}$ = 7 cm.

So We have,

• r = 7 cm.
• h = 6 cm.
• $\tt\pi = \dfrac{22}{7}.$

By putting the values in above formula,

$\\ \tt\mapsto Volume = \dfrac{1}{3}\pi r^2 h.$

$\\ \tt = \frac{1}{ \cancel3} \times \frac{22}{ \cancel7} \times \cancel{7} \: cm \times 7 \: cm \times \cancel6 \:cm .$

$\\ \tt = 1 \times 22 \times 1 \: cm \times 7 \: cm \times 2 \: cm.$

$\\ \tt = 44 \: cm {}^{2} \times 7 \: cm.$

$\\ \blue{ \large \underline{\boxed{\bf = 308 \: \: cm {}^{3} }}}$

$\bf\therefore$ The Required Volume Of The Cone Is 308 cm³.