Question

find the volume of cube whose side is (x+3) units (where x>0)​

Answer 1

volume of cube=a^3

=(X+3)^3

= x^3+3^3+3(X)(3)

(X+3)

= x^3+27+9x(X+3)

= x^3+27+9x^2+27x

=x^3+9x^2+27x+27

Answer 2

Answer:

volume of cube is a^3 where a is side of cube

Step-by-step explanation:

side = x+3

volume=

${x + 3}^{3}$

${x}^{3} + {3}^{3} + 3 \times x \times 3(x + 3) \\ {x}^{3} + 27 + 9x(x + 3) \\ {x}^{3} + 27 + 9 { x }^{2} + 27x \\ {x}^{3} + 9 {x}^{2} + 27x + 27$

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