Math, asked by sachinsanadi333, 3 months ago

find the volume of cylinder whose height and radius area 21cm and 2cm respectively​

Answers

Answered by suraj5070
350

 \sf \bf \huge {\boxed {\mathbb {QUESTION}}}

 \tt Find\: the \:volume\: of \:cylinder\: whose\: height \:and\\\tt radius \:area \:21 \:cm\: and\: 2\:cm\: respectively.

 \sf \bf \huge {\boxed {\mathbb {ANSWER}}}

 \sf \bf {\boxed {\mathbb {GIVEN}}}

  •  \bf Height \:of \:the \:cylinder =21\:cm
  •  \bf Radius \:of \:the \:cylinder =2\:cm

 \sf \bf {\boxed {\mathbb {TO\:FIND}}}

  •  \bf Volume \:of \:the \:cylinder

 \sf \bf {\boxed {\mathbb {SOLUTION}}}

 {\pink {\underline {\bf {\pmb {Volume \:of \:the \:cylinder}}}}}

 {\blue {\boxed {\boxed {\boxed {\green {\pmb {V=\pi {r}^{2} h}}}}}}}

  •  \sf V=volume \:of \:the \:cylinder
  •  \sf r=radius \:of \:the \:cylinder
  •  \sf h=height \:of \:the \:cylinder

 {\underbrace {\overbrace {\pmb {\orange {Substitute \:the \:values}}}}}

 \bf \implies V=\dfrac{22}{7}\times {\big(2\big)}^{2}\times 21

 \bf \implies V=\dfrac{22}{\cancel{7}}\times 4\times \cancel{21}

 \bf \implies V=22\times 4\times 3

 \implies{\blue {\boxed {\boxed {\purple {\mathfrak {V=264\:{cm}^{3}}}}}}}

 {\underbrace {\red {\overline {\red {\underline {\red {\sf {\pmb {{\therefore} The\:volume \:of \:the \:cylinder \:is\:264\:{cm}^{3}}}}}}}}}}

 \sf \bf \huge {\boxed {\mathbb {HOPE \:IT \:HELPS \:YOU}}}

__________________________________________

 \sf \bf \huge {\boxed {\mathbb {EXTRA\:INFORMATION}}}

 \sf Curved \:surface \:area \:of\:the \:cylinder =2 \pi rh

 \sf Total \:surface \:area \:of\:the \:cylinder =2\pi r(r+h)

 \sf Volume \:of\:the \:cylinder =\pi{r}^{2}h

Answered by Anonymous
187

Answer:

 \large  \underline\red{\sf \pmb{Given}}

  • ➛ Height of Cylinder = 21 cm
  • ➛ Radius of Cylinder = 2 cm

 \large \underline \red{\sf \pmb{To \:  Find}}

  • ➛ Volume of Cylinder

 \large \underline \red{ \sf \pmb{Using \:  Formula }}

 \circ\underline {\boxed{\sf \purple{Volume \: of \: Cylinder =  {\pi} {r}^{2} h}}}

Where

  •   \leadsto \tt\pi =  \dfrac{22}{7}
  •   \leadsto\tt{r = radius \: of \: cylinder}
  •  \leadsto \tt{h =  height \: of \: cylinder}

\large\underline\red{\sf\pmb{Solution}}

 \implies{\sf {Volume \: of \: Cylinder =  {\pi} {r}^{2} h}}

  • ⇒ Substituting the values

{\implies{\sf {Volume \: of \: Cylinder =  { \dfrac{22}{7} } \times  {2}^{2}  \times 21}}}

{\implies{\sf {Volume \: of \: Cylinder =  { \dfrac{22}{\cancel{7}}} \times 2 \times 2  \times {\cancel{ 21}}}}}

{\implies{\sf {Volume \: of \: Cylinder =  {22\times 2 \times 2 \times 3  }}}}

{\implies{\sf {Volume \: of \: Cylinder =  {264 \:  { cm}^{3}   }}}}

 \large \star\underline{\boxed{\sf \purple {Volume \: of \: Cylinder =  {264 \:  { cm}^{3}   }}}}

  • Henceforth,The volume of Cylinder is 264 cm³.

 \large \underline  \red{\sf \pmb{Know \:  More }}

Cylinder

➣ A cylinder has two flat ends in the shape of circles. These two faces are connected by a curved face that looks like a tube. If you make a flat net for a cylinder, it looks like a rectangle with a circle attached at each end.

  • Cylinder - A cylinder is a shape with two circular ends connected by a curved face.
  • Face - A cylinder has three faces. Two are flat circles and the third is curved into a tube.
  • Edge - An edge is the line where two faces meet. Cylinders have two edges that run around the two circular ends and connect with the curved face.
  • Net - The net of a cylinder is formed of two circles, with one attached to each end of a rectangle.
  • Circle - The two circular ends are flat on the cylinder so look the same in the flat net.
  • Rectangle - The tube part of a cylinder looks like a rectangle in the flat net. To make the cylinder, it has to be curved around to follow the edges of the circular ends.

Diagram of Cylinder

\setlength{\unitlength}{1mm}\begin{picture}(5,5)\thicklines\multiput(-0.5,-1)(26,0){2}{\line(0,1){40}}\multiput(12.5,-1)(0,3.2){13}{\line(0,1){1.6}}\multiput(12.5,-1)(0,40){2}{\multiput(0,0)(2,0){7}{\line(1,0){1}}}\multiput(0,0)(0,40){2}{\qbezier(1,0)(12,3)(24,0)\qbezier(1,0)(-2,-1)(1,-2)\qbezier(24,0)(27,-1)(24,-2)\qbezier(1,-2)(12,-5)(24,-2)}\multiput(18,2)(0,32){2}{\sf{r}}\put(9,17.5){\sf{h}}\end{picture}

  • Request-Please see the answer from website Brainly.in.
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