find the volume of gas at N.T.P (a) 14g of n2(b) 6.022*10^23 molecules of NH3
Answers
Answered by
0
What's your doubt?
Chemistry
Bookmark
6.022×10
22
molecules of N
2
at NTP will occupy a volume of:
share
Share
Answer
Correct option is
B
2.24 litres
The volume occupied by the 1mole of N
2
=22.4l
So, the 1mole=6.022×10
23
molecules of N
2
=
6.022×10
23
22.4
So, 6.022×10
22
molecules of N
2
would occupy volume
=
6.022×10
23
l
22.4
×6.022×10
22
=2.24l
Thus ,the right option is B
Similar questions