Question

find the volume of iron required to make an open box whose external diamensions are 36cm* 25cm*16.5cm.the box being 1.5 cm thick throughout.if 1 cm^3 of iron weights 8.5 grams, find the weight of the empty box in kilograms​

Answer 1

the volume of iron required to make an open box whose external dimensions are 36cm* 25cm*16.5cm, the box being 1.5 cm thick throughout is 3960 cm^3 . if 1 cm^3 of iron weights 8.5 grams, then 33.66 kg is the weight of the empty box in kilograms​.

• Given
• The length of open box = 36 cm
• The width of open box = 25 cm
• The height of open box = 16.5 cm
• External volume of the box = 36 × 25 × 16.5 = 14850 cm^3

• The thickness of iron = 1.5 cm
• Therefore the internal length open box = 36 - (1.5×2) = 33 cm
• Internal width open box = 25 - (1.5×2) = 22 cm
• Internal height open box =16.5 - 1.5=15 cm  (as the box is open)
• Internal volume of the open box = 33 × 22 × 15 = 10890 cm^3
• Volume of iron = External volume − Internal volume= 14850 - 10890 = 3960 cm^3
• 1 cm^3 of iron = 8.5 grams

• Therefore, the total weight of the box = 3960 × 8.5 = 33660 g= 33.66 kg.