Question

find the volume of iron required to make an open box whose external dimensions are 36 cm *25cm*16.5 cm, the box being 1.5 cm thick throughout.If 1cm cube of iron weight 8.5 grams,find the weight of the empty box in kilograms​

Answer 1

Answer:

External length = 36 cm

External width = 25 cm

External height = 16.5 cm

External volume of the box

Thickness of iron = 1.5 cm

∴ Internal length cm

Internal width cm

Internal height cm (as the box is open)

Internal volume of the box

Volume of iron = External volume − Internal volume

Given:

Total weight of the box

Step-by-step explanation:

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