find the volume of iron required to make an open box whose external dimensions are 36 cm *25cm*16.5 cm, the box being 1.5 cm thick throughout.If 1cm cube of iron weight 8.5 grams,find the weight of the empty box in kilograms
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Answer:
External length = 36 cm
External width = 25 cm
External height = 16.5 cm
External volume of the box
Thickness of iron = 1.5 cm
∴ Internal length cm
Internal width cm
Internal height cm (as the box is open)
Internal volume of the box
Volume of iron = External volume − Internal volume
Given:
Total weight of the box
Step-by-step explanation:
hope it helped
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