Question

Find
the
volume
of
iron
required
to
make
an
open
box
whose
external
dimensions
are
36
cm
x
25
cm
x16.5
cm
,
the
box
being
1.5
cm
thick
throughout
.​

Answer 1

Answer:

step by step explanation.

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Answer 2

Solution :

External length = 36 cm

External width = 25 cm

External height = 16.5 cm

Volume of cuboid = Length × Breadth × Height

External volume of the box = 36 × 25 × 16.5

14850 cm³

Thickness of iron = 1.5 cm

Internal length = 36 – (1.5 × 2) = 33 cm

Internal width = 25 – (1.5 × 2) = 22 cm

Internal height = 16.5 – 1.5 = 15 cm (As the box is open)

Volume of cuboid = Length × Breadth × Height

Internal volume of the box = 33 × 22 × 15

10890 cm3

Volume of iron = External volume – Internal volume

14850 – 10890

3960 cm³

1 cm³ of iron = 8.5 grams

Total weight of the box = 3960 × 8.5

33.66 kilograms.

hope it helps you !!!