Question

Find the volume of iron used to make a box which is open at one end. The outer
dimensions of the box is 1.35m, 1.08m and 90cm. The thickness of box is
2.5cm. Find the volume in m
m3.​

Answer 1

Answer:

ANSWER

REF.Image

New length = 1.35−2(0.025)

=1.35−0.05

=1.3m

New breadth = 1.08−2(0.025)

=1.03m

New height = 0.9−2(0.025)

=0.85m

Thickness of iron = 2.5 cm

= 0.025 m

Capacity or volume of cistern = l×b×h

=1.3×1.03×0.85

=1.138m

3

Volume of iron used = Volume of cistern (without considering the thickness of iron) - Volume of cistern (after considering the thickness of iron)

=L×B×H−l×b×h

=(1.35×1.08×0.9)−(1.138)

=1.312−1.138

=0.174m

3

Answer 2

Answer:

★the volume of the iron used.

⋆New length = 1.35−2(0.025)

• =1.35−0.05
• =1.3m

⋆New breadth = 1.08−2(0.025)

• =1.03m

⋆New height = 0.9−2(0.025)

• =0.85m

⋆Thickness of iron = 2.5 cm

• = 0.025 m

⋆Capacity or volume of cistern = l×b×h

• =1.3×1.03×0.85
• =1.138m

★Volume of iron used = Volume of cistern (without considering the thickness of iron) - Volume of cistern (after considering the thickness of iron)

• =L×B×H−l×b×h
• =(1.35×1.08×0.9)−(1.138)
• =1.312−1.138
• =0.174m

Hope it helps u....