find the volume of metal in the hollow pipe of internal radius 3 cm ,metal 1 cm thick and length 6 cm
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Hi.
Here is your answer---
Given---
Outer Radius(R) = 3 cm.
Inner Radius(r) = 1 cm.
Length(h) = 6 cm.
Using the Formula,
Volume of Material(or Metal) = π h( R² - r²)
= (22/7) × 6 × (3² - 1²)
= (22/7) × 6 × ( 9 - 1)
= (22/7) × 6 × 8
= 1056 cm³.
Thus, the volume of the metals in th pipe is 1056 cm³.
______________________
Hope it helps.
Have a nice day.
Here is your answer---
Given---
Outer Radius(R) = 3 cm.
Inner Radius(r) = 1 cm.
Length(h) = 6 cm.
Using the Formula,
Volume of Material(or Metal) = π h( R² - r²)
= (22/7) × 6 × (3² - 1²)
= (22/7) × 6 × ( 9 - 1)
= (22/7) × 6 × 8
= 1056 cm³.
Thus, the volume of the metals in th pipe is 1056 cm³.
______________________
Hope it helps.
Have a nice day.
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