find the volume of metal used to construct a hollow metallic sphere of internal and external diameter 10cm & 13cm respectively( use pie = 3.14)
Answers
Answered by
131
Hi ,
Dimentions of the hollow mettalic sphere are,
i ) Internal diameter ( d ) = 10 cm
Internal radius ( r ) = d / 2
r = 10 /2 = 5 cm
ii ) External diameter ( D ) = 13 cm
External radius ( R ) = 13 / 2 = 6.5 cm
iii ) volume of the hollow metallic sphere
= (4 / 3 ) × pi ( R^3 - r^3 )
= ( 4 / 3 ) × 3.14 × [ ( 6.5 )^3 - 5^3 ]
= ( 4/3 ) × 3.14 × [ 274.625 - 125 ]
= 4.187 × 149.625
= 26.48 cm^3 ( approx )
I hope this helps you.
****
Dimentions of the hollow mettalic sphere are,
i ) Internal diameter ( d ) = 10 cm
Internal radius ( r ) = d / 2
r = 10 /2 = 5 cm
ii ) External diameter ( D ) = 13 cm
External radius ( R ) = 13 / 2 = 6.5 cm
iii ) volume of the hollow metallic sphere
= (4 / 3 ) × pi ( R^3 - r^3 )
= ( 4 / 3 ) × 3.14 × [ ( 6.5 )^3 - 5^3 ]
= ( 4/3 ) × 3.14 × [ 274.625 - 125 ]
= 4.187 × 149.625
= 26.48 cm^3 ( approx )
I hope this helps you.
****
Answered by
2
Answer:
626.4300
Step-by-step explanation:
external radius =13/2
=6.5
internal radius = 10/2
= 5
volume = 4/3×3.14×(6.5³- 5³)
= 4/3×3.14×(274.625-125)
= 4/3×3.14×149.625
=1879.2900/3
=626.43 l
Similar questions