find the volume of o2 at stp for combustion of 96 gm propane
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C3H8 +5O2=======> 3CO2 + 4H2O. 1 mole or 22.4 Litres of Propane requires (5 x22. 4)= 112 Litres of oxygen at STP.
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(C3H8) is: [C=12,O=16, H=1, Molar Volume =22.4 dm3 at S.T.P]. A ... So, 0.2 mole propane requires 5×{22.4}×{0.2} = 22.4 litre O2 ... Get Instant Solutions, 24x7
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