Question

Find the volume of oxygen required and sulphur trioxide formed by the oxidation of 0.01 mole of Sulphur dioxide molecule

Answer 1

Answer:

so2 + 1/2 o2 = so3

for 1 mole of so2 0.5 mole o2 required

then for 0.01 mole of so2 required 0.005 mole o2 and 1 mole = 22.4 litre

0.005 mole o2 = 22.4× 0.005