Question

Find the volume of rectangular boxes with the following length,

breadth and height respectively :

x²y , 2x³y³ , 3xy²​

Answer 1

Answer:

Volume = lbh

              = x²y × 2x³y³ × 3xy²

              = 6(x^6)(y^6) unit³

Answer 2

$\large\sf\underline{Correct\: Question:-}$

Find the volume of rectangular boxes with the following length , breadth and height respectively :

• x²y , 2x³y³ , 3xy²

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$\large\sf\underline{Given:-}$

• Length = x²y

• Breadth = 2x³y³

• Height = 3xy²

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$\large\sf\underline{To\:find:-}$

• Volume of the rectangular boxes .

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$\large\sf\underline{Solution:-}$

We know ,

$\small{\underline{\boxed{\mathrm\pink{Volume\:of\: rectangle=length×breadth×height}}}}$

Now substituting the value in the formula :

$\sf⟹\:Volume=x²y × 2x³y³ × 3xy²$

$\sf⟹\:Volume=2x^{2+3}y^{1+3} × 3xy²$

$\sf⟹\:Volume=2x^{5}y^{4} × 3xy²$

$\sf⟹\:Volume=6x^{5+1}y^{4+2}$

${\sf{{\purple{⟹\:Volume=6x^{6}y^{6} }}}}$

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$\large\rm\red\star\:\underline{More\:to\:know:-}$

• ‎When you multiply monomials, first multiply the coefficients and then multiply the variables by adding the exponents.

• Note that when you multiply monomials with same base, you can add their exponents. This is called the Product of Powers Property.

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