Question

Find the volume of right circular
Cone whose diameter is 6cm &
Slant height is 5cm.​

Answer 1

$\huge{\text{\underline{\underline{Solution:}}}}$

It is given that Diameter of cone is 6cm

Radius will be 3cm as it's half of the diameter

Slant height is 5cm

Formula to find volume is 1/3πr²h

height h = √l²-r²

=√5²-3² = √25-9 = √16 = 4cm

Therefore, height is 4cm

Now, substituting the values in formula

1/3πr²h

1/3×22/7×3×3×4

Volume is approximately 48cm³

Answer 2

$\large \underline{ \underline{ \sf \: Solution : \: \: \: }}$

Given ,

$\star$Diameter = 6 cm

$\star$So , radius (r) = 6/2 = 3 cm

$\star$Slant height = 5 cm

$\star$ Height (h) = 4 cm

We know that ,

$\large \fbox{\fbox{ \sf Volume \: of \: cone = \frac{1}{3} \times \pi {r}^{2} h}}$

$\to \sf volume = \frac{1}{3} \times \frac{22}{7} \times {(3)}^{2} \times 4 \\ \\ \to \sf volume = \frac{22 \times 36}{21} \\ \\ \to \sf volume = \frac{792}{21} \\ \\ \to \sf volume = 37.7 \: \: {cm}^{3}$

Hence , the required value is 37.7 cm³