Question

find the volume of steel used in making hemispherical shell of radii 6cm and 7cm​

Answer 1

Answer:

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Answer 2

Given:

A hemispherical shell of radii 6 cm and 7cm​

To find:

The volume of steel used in making the hemispherical shell

Solution:

The inner radius of the hemispherical shell, r = 6 cm

The outer radius of the hemispherical shell, R = 7 cm

We know,

$\boxed{\bold{Volume\:of\:a \:hemisphere = \frac{2}{3} \pi r ^3}}$

Now,

The volume of the steel used in making the hemispherical shell is,

= [Outer volume of shell] - [Inner volume of shell]

= $\frac{2}{3} \pi R ^3 - \frac{2}{3} \pi r ^3$

= $\frac{2}{3} \pi [R ^3 - r ^3]$

on substituting the values of R and r, we get

= $\frac{2}{3} \times \frac{22}{7}\times [7 ^3 - 6 ^3]$

= $\frac{2}{3} \times \frac{22}{7} \times [343 - 216]$

= $\frac{2}{3} \times \frac{22}{7} \times 127$

= $\bold{266.1 \: cm^3}$

Thus, the volume of steel used in making the hemispherical shell of radii 6cm and 7cm​ is → 266.1 cm³.

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Also View:

find the volume of metal used in making a hollow hemisphere ball with internal and external diameter 4 cm and 10 respectively.

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