Find the volume of the box whose area of adjacent surface are 40m square,20m square and 8m square respectively
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Answer:
Volume of box = 80m³
Step-by-step explanation:
Let the edges of the box be represented as a, b and c
=> Area of adjacent surfaces will be a*b, b*c and a*c
We are given that these areas are 40m², 20m² and 8m²
=> a*b = 40 ; b*c = 20 and a*c = 8
a*b = 40 => b = 40/a
b*c = 20 => c = 20/b
a*c = 8
=> a*(20/b) = 8
but b = 40/a
=> a*(20/(40/a)) = 8
=> a*(20a/40) = 8
=> a²/2 = 8
=> a² = 16
=> a = 4
On substituting, we get:
b = 40/a = 40/4 = 10
c = 8/a = 8/4 = 2
The edges of the box are 4m, 10m and 2m
=> Volume of box = 4*10*2 m³ = 80m³
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