Question

Find the volume of the cuboid whose dimensions are (x +3) ,(x+5) &(x+2)

please answer​

Answer 1

Answer:

first find the value of x

Step-by-step explanation:

then put and answer out

Answer 2

Answer:

The volume of the cuboid with given dimensions is $x^3+10x^2+31x+30$

Step-by-step explanation:

If a cuboid has dimensions $l,b$ and $h$, then its volume is,

$Volume =l\times b\times h$

Given the measurements of the cuboid, $(x+3), (x+5)$ and $(x+2)$. So the volume is,

$Volume = (x+3)(x+5)(x+2)$

We need to expand the brackets to get the volume. First, we shall multiply the first two terms.

$(x+3)(x+5)=x(x+5)+3(x+5)=x^2+5x+3x+15=x^2+8x+15$

Then

$(x+3)(x+5)(x+2)=(x^2+8x+15)(x+2)\\\\= x(x^2+8x+15)+2(x^2+8x+15)\\\\=x^3+8x^2+15x+2x^2+16x+30\\\\= x^3+10x^2+31x+30$

Hence the volume is $x^3+10x^2+31x+30$