Question

Find the volume of the largest
rectangular parallelopiped that can be
inscribed in the ellipsoid of resvolution
4x²+4y2 + 9z² = 36​

Answer 1

Answer:

288√3 cube unit

Step-by-step explanation:

Here 4x^2 + 4y^2 + 9z^2 = 36

Dividing by 36 both side and we get ,

(x^2) / 9 + ( y^2 ) /9 + ( z^2 ) / 4 = 1

Now we know ,

the volume of the largest rectangular parallelepiped that can be inscribed in the ellipsoid (x^2) / a + ( y^2 ) /b + ( z^2 ) / c = 1 is 8abc / 3√3 = ( 8 × 9 × 9 × 4 ) / 3√3 = 288√3 cube unit