find the volume of the oxygen required to burn 36 grams of carbon completely at STP
Answers
1 mole of Carbon combines with 1 mole of molecular oxygen to form carbon dioxide.
1 mole of carbon weighs 12 grams. Hence 36 grams indicates there is 3 moles of carbon. One mole of molecular oxygen weighs 32 grams and it's volume should be 22.4 litres at STP. Hence we require 3 moles of molecular oxygen to burn completely with 3 moles of carbon
Hence we require about 22.4 x 3 = 67.2 litres of molecular oxygen.
Answer:
In chemistry, stoichiometry is the measurement of the ratios in which different substances or elements interact.
Explanation:
- Stoichiometry is a crucial idea in chemistry that enables us to compute reactant and product amounts using balanced chemical equations.
- We employ the ratios from the balanced equation in this situation.
- Generally speaking, the amount of substance present determines how all reactions will behave.
- The laws of conservation of mass, energy, and weights or volumes serve as the foundation for the rules used to determine stoichiometric relationships.
- Carbon dioxide is created when 1 mole of carbon and 1 mole of molecule oxygen mix.
- Carbon weights 12 grammes per mole. 36 gramd therefore shows that there are 3 moles of carbon. At STP, a mole of molecular oxygen should have a volume of 22.4 litres and a mass of 32 grams.
Consequently, in order for 3 moles of carbon and 3 moles of molecular oxygen to totally burn,
In light of this, we need roughly 22.4 x 3 = 67.2 litres of molecular oxygen.
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