Question

find the volume of the region between the cone z^2=x^2+y^2 and z^2=3(x^2+y^2) and bounded above by the sphere x^2+y^2+z^2=16

Answer 1

Answer:

find the volume of the region between the cone z^2=x^2+y^2 and z^2=3(x^2+y^2) and bounded above by the sphere x^2+y^2+z^2=16

Step-by-step explanation:

find the volume of the region between the cone z^2=x^2+y^2 and z^2=3(x^2+y^2) and bounded above by the sphere x^2+y^2+z^2=16

Answer 2

Step-by-step explanation:

the sum you will try it because of