Find the volume of the solid obtained by revolving about x-axis, of the part of the parabola x^2=16y cut off by the latus-rectum.
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For parabola,
y
2
=4ax
Latus Rectum is the line x=a
Area required=Area OLSL'
=2×AreaOSL
=2×∫
0
a
ydx
=2×∫
0
a
4ax
dx (∵y
2
=4ax)⇒y=
4ax
)
=2×∫
0
a
4a
x
dx
=4
a
∫
0
a
x
dx
=4
a
∫
0
a
x
dx
=4
a
2
3
x
2
3
=
3
8
a
a
2
3
=
3
8
a
2
1
a
2
3
=
3
8
a
2
4
=
3
8
a
2
Step-by-step explanation:
C IS THE ANS
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