find the volume of wood used to make a closed rectangle box of outer dimensions 60cm×45cm×32cm the thickness of wood being 2.5cm all around also find the capacity of box
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l=60cm
b=45cm
h=32cm
Volume=60×45×32==>86400cm³
Volume regarding thickness
Thickness will be double =2.5×2=5
l=60-5cm== >55cm
b=45-5cm==>40cm
h=32-5cm==>27cm
Then,
Volume=55×40×27==>59400cm³
Volume of wood
=Volume of original rectangular box-Volume after thickness subtracted.
==>86400-59400
==>27000cm³
b=45cm
h=32cm
Volume=60×45×32==>86400cm³
Volume regarding thickness
Thickness will be double =2.5×2=5
l=60-5cm== >55cm
b=45-5cm==>40cm
h=32-5cm==>27cm
Then,
Volume=55×40×27==>59400cm³
Volume of wood
=Volume of original rectangular box-Volume after thickness subtracted.
==>86400-59400
==>27000cm³
ali157:
Tnks
Answered by
0
volume of wood = surface area of box × Thickness of wood
= 2(60*45+45*32+32*60)*2.5 = 30300cm^3
Volume of box = 60*45*32= 86400 cm^3
= 2(60*45+45*32+32*60)*2.5 = 30300cm^3
Volume of box = 60*45*32= 86400 cm^3
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