Question

Find the volume of wood used to make a closed rectangular box of outer dimensions 60cm ×45cm×32cm , the thickness of wood being 2.5cm all around. Also find the capacity of the box.​

Answer 1

Answer:

L x B x H

Length

Beadth

Height

L= Length

B= Bead th

H= Height

Step-by-step explanation:

60 x 45 x 32 = 86400

86400x2.5

2.5 =half

86400÷2.5

Divided Answer

2.5=25

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Answer 2

$\boxed{\huge\mathrm{Solution}}$

Outer Dimensions = 60cm × 45cm × 32cm

Thickness of wood = 2.5cm

$\mathrm{l= 60-2(2.5) = 55cm}$

$\mathrm{b= 45 -2(2.5) = 40cm}$

$\mathrm{h = 32 - 2(2.5) = 27cm}$

$\therefore\mathrm{Capacity \: of \: the \: box }$

$\mathrm{ = (55× 40 × 27) {cm}^{3} }$

$\mathrm{ = 59400 {cm}^{3} }$

$\mathrm{Total \: volume \: of \: the \: box}$

$\mathrm{ = ( 60 \times 45 \times 32) {cm}^{3} }$

$\mathrm{ = 86400 {cm}^{3} }$

Volume of wood used =Total volume - Actual capacity

= 86400cm³ − 59400cm³

= 27000cm³

Hence, the volume of wood used = 27000cm³