Question

find the volume surface area of a cuboid of length 10 m, breath 7 m , and height 5 m . ​

Answer 1

Step-by-step explanation:

Volume of a cuboid = l*b*h

Volume of the surface = 10*7*5

Volume =350 m cube.

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Answer 2

AnswEr :

$\normalsize\bullet\:\sf\ Length = 10m$

$\normalsize\bullet\:\sf\ Breadth = 7m$

$\normalsize\bullet\:\sf\ Height = 5m$

♡Reference of Image is shown in diagram

$\setlength{\unitlength}{0.74 cm}\begin{picture}(12,4)\thicklines\put(6,6){\line(1,0){5}}\put(6,9){\line(1,0){5}}\put(11,9){\line(0,-1){3}}\put(6,6){\line(0,1){3}}\put(4,7.3){\line(1,0){5}}\put(4,10.3){\line(1,0){5}}\put(9,10.3){\line(0,-1){3}}\put(4,7.3){\line(0,1){3}}\put(6,6){\line(-3,2){2}}\put(6,9){\line(-3,2){2}}\put(11,9){\line(-3,2){2}}\put(11,6){\line(-3,2){2}}\put(8,5.5){10 m}\put(4,6.3){7 m}\put(11.2,7.5){5 m}\end{picture}$

Put the available values of Length, Breadth and Height in formulae to get correct answer and the point that should be remember is that the given values are in meter(m).

$\rule{170}2$

☯ $\large\underline{\textsf{Volume \: of \: Cuboid:}}$

$\normalsize\bigstar\:{\boxed{\sf{Volume \: = \: Length \times\ Breadth \times\ Height}}}$

$\normalsize\dashrightarrow\quad\sf\ Volume = 10 \times\ 7 \times\ 5$

$\normalsize\dashrightarrow\quad\sf\ Volume = 10 \times\ 35$

$\normalsize\dashrightarrow\quad\sf\ Volume = 350$

$\normalsize\dashrightarrow\quad{\underline{\boxed{\sf \red{Volume = 350m^{3}}}}}$

$\therefore\:\underline{\textsf{Hence, \: the\: Volume \: of \: Cuboid \: is}{\bf{\: 350m^{3} }}}$

$\rule{100}1$

☯ $\large\underline{\textsf{Surface \: area \: of \: Cuboid:}}$

$\normalsize\bigstar\:{\boxed{\sf{Surface \: area \: = \: lb + bh + hl}}}$

$\normalsize\ : \implies\quad\sf\ Surface \: area = 10 \times\ 7 + 7 \times\ 5 + 5 \times\ 10$

$\normalsize\ : \implies\quad\sf\ Surface \: area = 70 + 35 + 50$

$\normalsize\ : \implies\quad\sf\ Surface \: area = 105 + 50$

$\normalsize\ : \implies\quad\sf\ Surface \: area = 155$

$\normalsize\ : \implies\quad{\underline{\boxed{\sf \red{ Surface \: area = 155m^{2} }}}}$

$\therefore\:\underline{\textsf{Hence, \: the \: Surface \: area \: of \: cuboid \: is}{\bf{\: 155m^{2}}}}$